The given equation is
![y=6x-2](https://img.qammunity.org/2023/formulas/mathematics/college/7bx5syg27iqj23qqrvijg8b26z71mu71ud.png)
The slope of the given line is 6.
It is important to know that parallel lines have the same slopes, so the slope of the new line is 6.
Now, we use the point-slope formula to find the new line
![y-y_1=m(x-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/csobd57zth7rh9k4hz9amldzpq2owf0z4j.png)
Let's replace the point (-4,7) and the slope 6.
![\begin{gathered} y-7=6(x-(-4)) \\ y-7=6x+24 \\ y=6x+24+7 \\ y=6x+31 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/dn3bwv8b90cys9cr60dlooprkt4m543zae.png)
Hence, the equation of the new parallel line in slope-intercept is
![y=6x+31](https://img.qammunity.org/2023/formulas/mathematics/college/efxkekt2ng1lpzual4c8vo0sju5e6xa6pb.png)
In point-slope form is
![y-7=6(x+4)](https://img.qammunity.org/2023/formulas/mathematics/college/l7ltzp9it0056ny3188dgp7i1a81th5o9q.png)