Answer:
1125
Step-by-step explanation:
To evaluate the expression, we need to substitute x by 5 and y by 4, so we get:
![\begin{gathered} 3xy^0\cdot3x^2 \\ 3(5)(4)^0\cdot3(5)^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/z4p5ztkhaiklfsjxl5xuuxl69ypki6fe7h.png)
By properties of the exponents, any number to the power of 0 is equal to 1, and any number to the power of 2 is equal to that number multiplied by itself, so:
![3(5)(1)\cdot3(5)(5)](https://img.qammunity.org/2023/formulas/mathematics/college/hg1aur277znxq4v0v1zkdhor5qxn3fs7dd.png)
Now, we can multiply the terms of the expression to get:
![\begin{gathered} 15(1)\cdot15(5) \\ 15\cdot75 \\ 1125 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/zt4e6mv0w4s47prlfbd5pritsdifkwtcwp.png)
Therefore, the answer is 1125