121k views
4 votes
Linear Application: In the year 1980, an investment was worth $30200. In the year 1985, this investment was worth $36700. Select an answer at a rate of The value of this investment is Select an answer

1 Answer

4 votes

Wetbonescore, this is the solution:

Step 1: Let's calculate the diffrence of the investment in 1985 and 1980, as follows:

• Difference = 36,700 - 30,200

,

• Difference = 6,500

Step 2: Now, let's calculate the rate of change between 1985 and 1980, this way:

• Rate = 6,500/30,200 * 100

,

• Rate = 0.215 * 100

,

• Rate = 21.5%

,

• Rate = 22% (rounding to the next whole)

The value of this investment is increasing at a rate of 22%

User PBelanger
by
3.7k points