Given:
There are given that the length of a rectangle is 1 inch more than the width.
Step-by-step explanation:
Suppose the value of width is x.
Then,
According to the question, the length of a rectangle is 1 inch more than the width:
So,
The value of width is;

Now,
From the formula of area of a rectangle:

Then,

Then,
Put the value of x, i.e., 4, into the length and width.
So,

Final answer:
Hence, the dimension of the rectangle is shown below:
