For a three course meal we have to choose one option of each course, to determine how many possible posibilities we have we just need to multiply the number of possibilities on each couse, then we have:
![(5)(9)(3)=135](https://img.qammunity.org/2023/formulas/mathematics/college/5rg32867a446cw1jbho3dec50lpkqfopym.png)
Therefore, there are 135 possible 3-course meals.