You can use the following formula in order to calculate the Lateral area of the right cylinder given in the exercise:

Where "LA" is the lateral area of the cylinder, "r" is the radius and "h" is the height.
In this case you know that its diameter is:

Since the diameter of a circle is twice the radius:

Knowing that the height of the cylinder is:

You can substitute values into the formula and then evaluate, in order to find the lateral area:

Then, the answer is:
