Question

Use the given special right triangle to find the value of sin 6 2x TV 3 TT 3 х

Answer 1

hello

to solve this question, we need to use trigonometric ratio

using trigonometric ratio

SOHCAHTOA

`\begin{gathered} \text{SOHCAHTOA} \\ \text{SOH}=\sin \theta=(opp)/(adj) \\ \text{CAH}=\text{cos}\theta=(adj)/(hyp) \\ \text{TOA}=\text{tan}\theta=(opp)/(adj) \end{gathered}`

from the given angle, we can find the value of what is required of us

`\begin{gathered} \sin (\pi)/(3)=(opp)/(adj) \\ \sin (\pi)/(3)=\frac{\sqrt[x]{3}}{x} \\ \sin (\pi)/(3)=\sqrt[]{3} \end{gathered}`