Question

Multiple choice homework A 0.2 kg baseball is pitched with a velocity of +40 m/s and is then batted back off the pitcher with a velocity of -60m/s. What is the magnitude (size) of the change in the balls momentum A 4.0 KGM/s18:32B. 8.0 KGM/sC. 12.0 KGM/s D. 20.0 KGM/s

Answer 1

The formula for calculating momentum is expressed as

momentum = mass x velocity

From the information given,

mass of baseball = 0.2kg

initial velocity of baseball = 40

initial momentum of baseball = 0.2 x 40 = 8 kgm/s

final velocity of baseball = 60 m/s

final momentum of baseball = 0.2 x 60 = 12 kgm/s

Change in momentum = final momentum - initial momentum

Change in momentum = 12 - 8 = 4 kgm/s