Question

What are the solutions to the equation 6x2 - x - 40 = 0? A. x = -8/3, x = -5/2B. x = -8/3, x = 5/2 С. x = -2, x = 3 D. x = -6, x = 2

Answer 1

`\begin{gathered} \text{ Given that } \\ 6x^2-x-40=0 \end{gathered}`
`\begin{gathered} \text{ Therefore} \\ 6x^2-16x+15x-40=0 \\ \text{Hence,} \\ 2x(3x-8)+5(3x-8)=0 \\ \text{Thus} \\ (2x+5)(3x-8)=0 \\ \text{ therefore} \\ 2x+5=0;3x-8=0 \\ \text{this implies that} \\ x=(8)/(3);x=-(5)/(2) \end{gathered}`