Sum of consecutives
A + B + C + D = 28
B= A+2, C= A+2+2 ,D= A+2+2+2
Then
A+(A+2)+(A+4)+A+6= 28
A+A+A+A+2+4+6 = 28
4•A = 28- 2-4-6
then A = (28-12)/4 = 4
then consecutive evens are
4,6,8,10
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