The top left parabola is an upward facing parabola so it is in the form ax^2 The vertex is at (0,0)
It must be y = 5x^2
The parabola on the top right is shifted up by 5 units
A shift is ax^2 + k where k is the shift
y = ax^2 +5
Since it is an upwards facing parabola a must be positive
The only choice is
y = x^2 +5
The bottom left graph is an absolute value since it makes a v. Since it is pointing down, it is in the form
y = -a|x| since it is centered at (0,0)
The only equation of this form is
y = -3|x|
The bottom right graph is an absolute value since it makes a v. Since it is pointing up, it is of the form y = a|x|. It is shifted up 3 units since it is centered at x=0
y = a|x| +3
The only answer of this form is
y = |x| +3