Question

Find the value of c that make each expression a perfect square trinomial

Answer 1

To find the value of c in a perfect square trinomial, apply the formula:

`\begin{gathered} c=((b)/(2))^2 \\ \text{ Where} \\ ax^2+bx+c\Rightarrow\text{ Square trinomial} \end{gathered}`

So, in this case, you have

`\begin{gathered} z^2+22z+c \\ a=1 \\ b=22 \\ c=\text{ ?} \end{gathered}`
`\begin{gathered} c=((b)/(2))^2 \\ c=((22)/(2))^2 \\ c=(11)^2 \\ c=121 \end{gathered}`

Therefore, the value of c that makes the given expression a perfect square trinomial is

`c=121`