in this problem
the equation is of the form
y=a(b)^x
where
a is the initial value
a=190
x=0 -----> is the year 1990
so
y=190(b)^x
For year 1994 -----------> x=1994-1990=4 years
y=280
substitute
280=190(b^4)
solve for b
b^4=280/190
b=1.10
therefore
y=190(1.10)^x
In the year 2001
x=2001-1990=11 years
substitute
y=190(1.10)^11
y=542 rabbits