Question

Hi, can you help me answer this question please, thank you

Answer 1

Step1: Write out the formula for test statistic

`t=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt[]{n}}}`

Step2: Identify the given parameter in the question

`\begin{gathered} \mu=58.9 \\ \bar{x}=60.5 \\ n=18 \\ \sigma=13.4 \\ \text{where } \\ n=\text{sample size,}\bar{x}=\text{sample mean }\sigma=s\tan dard\text{ deviation } \end{gathered}`

Step3; Substitute the values into the formula

`\begin{gathered} t=\frac{60.5-58.9}{\frac{13.4}{\sqrt[]{18}}} \\ \\ t=(1.6)/((13.4)/(4.24)) \\ \\ t=(1.6)/(3.16) \end{gathered}`

Step4: Simplify the expression in the last line above

`\begin{gathered} t=(1.6)/(3.16) \\ \\ t=0.506 \end{gathered}`

Therefore the test statistics is 0.506 to 3 d.p