Question

Calculate the current produced for an electroscope with a surplus of 2.2 x1010 electrons that discharge in 0.60 s through a person's finger.

Answer 1

Given,

The number of electrons discharged, N=2.2×10¹⁰

The time duration, t=0.60 s

The charge of one electron is e=1.6×10⁻¹⁹ C

Thus the total charge discharged due to N numbers of electrons is,

`\begin{gathered} q=Ne \\ =2.2*10^(10)*1.6*10^(-19) \\ =3.52*10^(-9)\text{ C} \end{gathered}`

The electric current can be described as the time rate of flow of the charges.

Thus the current produced for an electroscope is given by,

`I=(q)/(t)`

On substituting the known values,

`\begin{gathered} I=(3.52*10^(-9))/(0.60) \\ =5.87*10^(-9)\text{ A} \end{gathered}`

Thus the current produced is 5.87×10⁻⁹ A