Question

Two balloons are held apart at a distance of2 amps and 0.2 m. One balloon has a charge of +4.5 xstance; 10^-6 C, and the other balloon has a charge ofe of the -2.5 x 10^-6 C. What is the amount ofHOW YOUR electrical force between the charges AND is itg= ,u= an attractive or repulsive force? SHOW YOURWORK!! Example: g= , u= , e = , S = ,smm

Answer 1

0.5N, attractive force

Explanation:

The Coulomb's law is:

`F_e=k(q_1\cdot q_2)/(r^2)`

The constant is equal to 9 * 10 ^ 9, we know the charges q1 and q2, and the distance between them, so if we replace we can calculate the value of the electric force.

Just like that:

`\begin{gathered} k=9\cdot10^9C^(-2)m^2N \\ q_1=4.5\cdot10^(-6)C \\ q_2=-2.5\cdot10^(-6)C \\ r=0.2 \\ \text{replacing:} \\ F_e=9\cdot10^9\cdot(4.5\cdot10^(-6)\cdot-2.5\cdot10^(-6))/(0.2) \\ F_e=0.5\text{ N} \end{gathered}`

The electric force between the two is 0.5 newton.

The force is repulsive if the charges have the same sign and it is attractive if the charges have opposite signs.

Therefore, in this case is attractive force