Question

An object with an initial velocity of 10 m/s accelerates at a rate of 3.5 m/s2 for 8 seconds. How far will it have traveled during that time? x = xo + vo t + ½ a t 2 g = 9.8 m/s2 (downward)

Answer 1

Given data:

*The initial velocity of an object is v_0 = 10 m/s

*The given acceleration is a = 3.5 m/s^2

*The given time is t = 8 s

The formula for the distance traveled during the time is given by the equation of motion as

`x=x_0+v_0t+(1)/(2)at^2`

*Here x_0 = 0 m is the initial position of the particle

Substitute the known values in the above expression as

`\begin{gathered} x=(0)+(10)(8)+(1)/(2)(3.5)(8)^2 \\ =80+112 \\ =192\text{ m} \end{gathered}`

Hence, the distance traveled during the time is x = 192 m