Question

How do the images change when the object distances change?

Answer 1

Step-by-step explanation:

this question is related to the mirror.

first, we will see the formula for how things are related to it.

The mirror formula is given as

`(1)/(f)=(1)/(v)+(1)/(u)`

Where

`f`

is the focal length of the mirror,

`v`

is the distance of the image from the mirror and

`u`

is the distance of the object from the mirror.

we can assume that the focal length of the mirror is some value let's say 10 cm.

and an object that is placed in front of the mirror is at a 15 cm.

plugging all the values in the above relation, we get

`\begin{gathered} (1)/(f)=(1)/(v)+(1)/(u) \\ (1)/(v)=(1)/(f)-(1)/(u) \\ (1)/(v)=(1)/(10)-(1)/(-15) \\ (1)/(v)=(5)/(30) \\ v=6\text{ cm} \end{gathered}`

we can see that image of the object will be formed at 6 cm towards the right.

now look at the formula again

`(1)/(v)=(1)/(f)-(1)/(u)`

as we increase the distance of the object the image of the object move in the right direction. or we can say distance of the image is also increase.

Thus, we can conclude that as we increase the object's distance, the distance of the image will also be increased in the opposite direction.