Question

200 Coulombs of charge passes through a point in a circuit for 0.6 minutes. what is the magnitude of the current flowing​

Answer 1

The magnitude of the current flowing through the circuit is calculated using the formula I = Q / t. With the charge of 200 Coulombs and the time of 0.6 minutes (converted to 36 seconds), the magnitude of the current is found to be 5.56 Amperes.

Step-by-step explanation:

To calculate the magnitude of the current flowing through a point in a circuit, we use the relationship that current (I) is equal to the charge (Q) divided by time (t), I = Q / t. The given charge is 200 Coulombs, and the time is 0.6 minutes. To find current in amperes, we need the time in seconds, so we first convert 0.6 minutes into seconds (0.6 minutes * 60 seconds/minute = 36 seconds).

Now we can use the formula:

I = Q / t = 200 C / 36 s

After performing this calculation, we find:

I = 5.56 Amperes

This is the magnitude of the current flowing through the circuit.

Answer 2

5.56 A

Step-by-step explanation:

From the question,

Q = it.............. Equation 1

Where Q = charges, i = current, t = time.

Make i the subject of the equation

i = Q/t.............. Equation 2

Given: Q = 200 coulombs, t = 0.6 minutes = (0.6×60) seconds

Substitite these values into equation 2

i = 200/(0.6×60)

i = 5.56 A

Hence the magnitude of the current flowing through the circuit is 5.56 A