Question

Two boys A and B are a two diametrically opposite points on a circle. at one instant the two start running on the circle​

Answer 1

is this the full question: Two boys A and B are at two diametrically opposite points on a circle. At one instant the two start running on the circle; A anticlockwise with constant speed v and B clockwise with constant speed 2v. In 2 minutes, they pass each other for the first time. How much later will they pass each other for the second time?

if yes than this is the answer:-

A speed = v

B speed = 2v

Time to meet = 2 minutes

d= pi r ( distance they have to run to meet)

they are running towards each other.

(2v+v)

speed = 3v

d=rt

pi*r = 3v*2

r= 6v/pi

circumference = 2* pi*r

=2*pi*(6v/pi)

=12v

...

Now distance to travel to meet = 12v

speed = 3v

t=d/r

t= 12v/3v

t= 4 minutes

I hope this helps a little bit.

Answer 2

Explanation:

let the distance travel by both be a&b

a has a distance of d1 like wise b

speed=distanc/time

d1=2v

d2=4v

total distance

d1+d2=180

2v+4v=180

6v=180

v=30

d1=2*30

d1=60

d2=4*20

d2=120

now start u get u starting

not that there meet at same point so now calculate the time they will trave in there various direction

time=distance/velocity

but they but move at a standard velocity