We have:
Total number of cards = 52
If you win then you will get = $70
If you lose then you will give him = $10
Therefore, first let us calculate the probability that three fives cards will be drawn with replacement:
![P(3\text{ fives cards)=}(4)/(52)*(4)/(52)*(4)/(52)=0.000455](https://img.qammunity.org/2023/formulas/mathematics/college/vnhxlxcwf5wp7crv44lg39me3yxwhnmc3s.png)
Next, the probability that it will not draw three fives in succession is:
![P(\text{not 3 fives cards)=}1-0.000455=0.999545](https://img.qammunity.org/2023/formulas/mathematics/college/br9nmqet5th9jrd2s8hr62e9xygezzh4hy.png)
Hence, for each game the expected return would be:
![0.000455*70-0.999545*10=0.03185-9.99545=-9.9636](https://img.qammunity.org/2023/formulas/mathematics/college/b9bpj44bwg58268omyas92nby6pu0py689.png)
For 30 times:
![-9.9636*30=-298.91](https://img.qammunity.org/2023/formulas/mathematics/college/fv9gudyn41jqw46z4o5v3mnw5hrpdqcwkr.png)
So, you lose $298.91
Answer:
Lose
$298.91