Question

A weightlifter lifts a 105 KG barbell and a height of 1.95 m in a .25 seconds how much power is demonstrated by the left

Answer 1

8026.2 J/s

Step-by-step explanation:

The power can be calculated as:

`P=(W)/(t)=(Fd)/(t)`

Where W is the work done and it is equal to the force done times the distance and t is the time.

In this case, the force is equal to the weight, so the force will be

F = (105 kg)(9.8 m/s²) =1029 N

Then, replacing the force F = 1029 N, the distance d = 1.95 m and the time t = 0.25 seconds, we get

`P=((1029N)(1.95m))/(0.25s)=8026.2\text{ J/s}`

Therefore, the power is 8026.2 J/s