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{2x+2y=2,2(x+y)=10}A. single solution B. no solution C. infinite solutions

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To find the number of solutions of a system of linear equations you need to identify the slope (m) in each equation:


y=mx+b

-If the slope is the same in both lines the system has no solution

-If the slope is different in the lines the system has one solution

-If the equation are the same (incluided the value of b) the system has infinitely many solutions

You have the next equations:


\begin{gathered} 2x+2y=2 \\ 2(x+y)=10 \end{gathered}

Write the equations in slope-intercept form y=mx+b (solve for y).

First equation:


\begin{gathered} 2y=-2x+2 \\ y=-(2)/(2)x+(2)/(2) \\ \\ y=-x+1 \end{gathered}

Second equation:


\begin{gathered} 2x+2y=10 \\ 2y=-2x+10 \\ y=-(2)/(2)x+(10)/(2) \\ \\ y=-x+5 \end{gathered}As the equations have the same slope m = -1, the system has no solution (the line doesn't cross each other)
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