We are given the following equation :
S +6HNO3 →H2SO4 + 6NO2 + 2H2O
So calculating how many grams of water can be made when 19.7 mole HNO3 is consumed. we will need to determine moles of water from the above equation,
1. 6 moles of nitric acid : 2 moles of water
∴19.7 moles of nitric acid : x ...( cross multiply and solve for xmol of water)
∴ x moles of water = (19.7 moles * 2 moles )/6
moles of water = 6.566
≈6.57moles
2. Calculate mass of water made:
Molecular mass of water (H2O ) ={ (1*2 ) + 16} = 18g/mol
n = m/ Mol Mass
∴ m = n* Mol Mass water
= 6.57 *18g/mol
mass water = 118.26g
rounding off to the nearest tenth ( leaving only one number after the decimal point) .
• So mass of water made = 118.3g