Question

Find the 70th term of the following arithmetic sequence.
13, 22, 31, 40,

Answer 1

634

Explanation:

Nth term of an arithmetic progression is given by:

Tn=a+(n-1)d

Where 'Tn' is the Nth term of A.P. , 'a' is the first term of A.P. , 'n' is the no. of terms and 'd' is the common difference.

22-13=9, 31-22=9, 40-31=9.

So, d=9

a=13

n=70

Put the values in the Formula.

T70=13+(70-1)*9=13+69*9=13+621=634

Answer 2

its 31 just trust me homie;)