Question

Find all angles, 0°< A<360°, that satisfy the equation below, to the nearest tenth

of a degree (if necessary).
3 tan A+75 = 0

Answer 1

143.3 degrees and 323.3 degrees

Explanation:

Given the equation

3tanA +√5 = 0

3tanA = -√5

tanA =-√5/3

tanA = (-0.7454)

A = arctan(-0.7453)

A = -36.699

Since tan is negative in 2nd and 4th quadrant

A = 180 - 36.699

A = 143.3 degrees

In the fourth quadrant

A = 360 - 36.699

A = 323.3degrees

Hence the value of A that satisfies the equation are 143.3 degrees and 323.3 degrees