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A person applies a 20N force for 2 seconds to a shopping cart with an initial momentum of -60kg m/s to slow it down. What is the change in momentum of the shopping cart?

1 Answer

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Given data

*The given force applied by the person is F = 20 N

*The given time is t = 2 seconds

The formula for the change in momentum of the cart is given as


\Delta p=F* t

Substitute the known values in the above expression as


\begin{gathered} \Delta p=20*2 \\ =40\text{ }(kg.m)/(s) \end{gathered}

Hence, the change in momentum of the shopping cart is 40 kg.m/s

User Jashandeep Sohi
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