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through (-2,3) and (5,-3) write the point slope form of the equation of the line through the given points

User Thoomas
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SOLUTION

CONCEPT: Equation of a Line

The point-slope form of the equation of a line is given as


\begin{gathered} y-y_1=m(x-x_1) \\ \text{where m=slope, (x}_1,y_1)\text{ is the point} \end{gathered}

From the questions, the given point are


\begin{gathered} x_1=-2,x_2=5 \\ y_1=3,y_2=-3 \end{gathered}

The slope m, of the line is given by


m=(y_2-y_1)/(x_2-x_1)

Substituting the values given we have


\begin{gathered} m=(-3-3)/(5-(-2))=(-6)/(7) \\ m=(-6)/(7) \end{gathered}

Then the point-slope form for the equation of the line is


y-3=-(6)/(7)(x-5)

User Deep Verma
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