In the given figure the diameter of the larger circle is 2.5 inches
and the diameter of the smaller circle is 0.8 inches.
The radius is given as, r = d/2 where d is the diameter.
Then,
the radius of the larger circle = R = 2.5/2 inches = 1.25 inches
and the radius of the smaller circle is = r = 0.8/2 inches = 0.4 inches
Now the area of the circle is given as
![\begin{gathered} A=\pi r^2 \\ where\text{ r is the radius of the circle} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/f6jkjlf9x9i5xx7tfw9y76nor7316mkzth.png)
So the area of the shaded portion will be
![\begin{gathered} Required\text{ area=}\pi R^2-\pi r^2 \\ Required\text{ area = }\pi[R^2-r^2]=(22)/(7)*[1.25^2-0.4^2] \\ Required\text{ area =3.14}*1.4025\text{ sq inches} \\ Required\text{ area = 4.40385 sq inches} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/v3hlf93lh55ohudtg5m9tqd86g7ut1su8w.png)
Hence the area of the shaded portion will be 4.40385 sq inches.