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Write an equation perpendicular to the given line through the given point. y= 1/4x + 3, through (4,1)

User Milco
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1 Answer

4 votes

y = -4x + 17

Step-by-step explanation:

1st equation: y= 1/4x + 3

Point (x, y) = (4,1)​

For one equation of line to be perpendicular to the other, the slope of one will be the negative reciprocal of the other one.

Equation of line form: y= mx + c

y= 1/4x + 3

Slope of the first = 1/4

reciprocal of the slope = 4/1

negative reciprocal = -(4/1) = -4

This means the slope of the second line = -4

we insert the slope and the point given in the equation formula to get the intercept (c):

Point (x, y) = (4,1)​

1 = -4(4) + c

1 = -16 + c

1 + 16 = c

c = 17

Equation y= mx + c becomes: y = -4x + 17

The equation perpendicular to the given line through the given point is y = -4x + 17

User OrigamiEye
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