Equation of the line
The equation of a line in slope-intercept form is:
y = mx + b
Where m is the slope and b is the y-intercept.
We are required to find the equation of a line that is perpendicular to the line
y = 5x + 4
and passes through the point (-5,2)
The first thing we need to do is to calculate the slope of the required line.
The slope of the given line is m1=5. Two lines are perpendicular if their slopes satisfy the equation:
m1 * m2 = -1
Solving for m2:
![m_2=-(1)/(m_1)=-(1)/(5)](https://img.qammunity.org/2023/formulas/mathematics/high-school/2a4ijf6aq4nimhtftre0r4c0e2yzj9f55q.png)
The equation of the required line is:
![y=-(1)/(5)x+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/h7hcfb3sk2dqigzea1upqxorufngljm42h.png)
To find the value of b, we substitute the given point (-5,2):
![2=-(1)/(5)(-5)+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/1zdrsy6mzr6kpnh4vf7rkai2apj3hmkikm.png)
Operating:
![2=1+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/vm4q4jfz49oz8996c3c9xyub1ehh1wpvt3.png)
Solving for b:
b = 1
Finally, our equation is:
![y=-(1)/(5)x+1](https://img.qammunity.org/2023/formulas/mathematics/high-school/zm7x46qpvn3yamgvi7l6u794g063xwnbxg.png)