Question

Determine the time constant of an LR circuit built using a 12.00 V battery, a 62.00 mH inductor and a 25.00 ohms resistor.

Answer 1

The time constant for an RL circuit is given by:

`\tau=(L)/(R)`

In this case the inductance is 62 mH and the resistance is 25 Ohms, then we have:

`\begin{gathered} \tau=(62*10^(-3))/(25) \\ \tau=2.48*10^(-3) \end{gathered}`

Therefoe, the atime constant is 0.00248 seconds