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The sum of two numbers is 30 and their quotient is 2

User Bill Clark
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1 Answer

5 votes

Let x, and y be the two numbers the problem is asking for, then we can set the following system of equations:


\begin{gathered} x+y=30, \\ (x)/(y)=2. \end{gathered}

Solving the second equation for x, we get:


\begin{gathered} (x)/(y)\cdot y=2\cdot y, \\ x=2y\text{.} \end{gathered}

Now, substituting x=2y in the first equation we get:


2y+y=30.

Solving for y we get:


\begin{gathered} 3y=30, \\ (3y)/(3)=(30)/(3), \\ y=10. \end{gathered}

Finally, we substitute y=10 in the first equation on the board and get:


x+10=30.

Solving for x we get:


\begin{gathered} x=30-10, \\ x=20. \end{gathered}

Answer: the numbers we are looking for are 20 and 10.

User BuraCULa
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