Question

Calculate the volume of a 0.323 mol sample of a gas at 265K an 0.900 atm

Answer 1

Answer: the volume of the gas under the conditions given is 7.80 L

Step-by-step explanation:

The question requires us to determine the volume of a gas that contains 0.323 mol and is at 265 K and 0.900 atm.

We can apply the equation of ideal gases to solve this problem, as shown below:

`P* V=n* R* T`

where P is the pressure of the gas (0.900 atm), V is the volume we want to calculate, n is the number of moles of gas (0.323 mol), R is the constant of gases and T is the temperature (265 K).

We can rearrange the equation to calculate the volume of the gas:

`PV=nRT\rightarrow V=(n* R* T)/(P)`

Since the pressure was given in atm and the temperature in K, we can use the following value for the constant of gases:

`R=0.082057(L.atm)/(mol.K)`

Note that the volume will be obtained in liters (L).

Applying the values provided by the question, we'll have:

`\begin{gathered} \begin{equation*} V=(n* R* T)/(P) \end{equation*} \\ \\ V=\frac{(0.323\text{ mol\rparen}*(0.082057\text{ L.atm/mol.K\rparen}*(265\text{ K\rparen}}{(0.900\text{ atm\rparen}}=7.80\text{ L} \end{gathered}`

Therefore, the volume of the gas under the conditions given is 7.80 L.