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A set of 4 consecutive integers adds up to 310. What is the value of the greatest integer?

User Rboling
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1 Answer

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We can define the 4 consecutive integers as n, n+1, n+2 and n+3.

The index n is a integer value.

We know that if we add them, we get 310.

Then, we can write:


\begin{gathered} n+(n+1)+(n+2)+(n+3)=310 \\ 4n+6=310 \\ 4n=310-6 \\ 4n=304 \\ n=(304)/(4) \\ n=76 \end{gathered}

Now that we know the value of n (n=76), we can calculate the value of our greatest integer, which has a value of n+3:


n+3=76+3=79

Answer: the greatest integer of the list is 79.

To verify, we can do:


76+77+78+79=310

User Anton Tcholakov
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