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Molly estimated the width of a poster to be 21 inches. The actual width is 26 inches. To the nearest tenth of a percent, what is the percent error of Molly's estimate? Enter your answer as a decimal in
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Molly estimated the width of a poster to be 21 inches. The actual width is 26 inches.

To the nearest tenth of a percent, what is the percent error of Molly's estimate?

Enter your answer as a decimal in the box.

User SemperAmbroscus
by
4.5k points

2 Answers

8 votes

Answer:

19.2

21-26/26=0.192x100=19.2

Explanation:

dont worry about the negative sign

User Muluken Getachew
by
4.7k points
8 votes

Answer:

19.2

Explanation:

User Wilson Delgado
by
4.6k points
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