ANSWER
![\begin{equation*} 4.67*10^(-9)\text{ }N \end{equation*}](https://img.qammunity.org/2023/formulas/physics/college/jhmzwkrpc3x1k4mzyagh50qudt4izloa4w.png)
Step-by-step explanation
Parameters given:
Mass of the student, M = 70 kg
Mass of the textbook, m = 1 kg
Distance, r = 1 m
To find the gravitational force acting between the student and the textbook, apply the formula for gravitational force:
![F=(GMm)/(r^2)](https://img.qammunity.org/2023/formulas/physics/college/p20kk3pgzhlhcesfssdvelq3rdwww1ttiw.png)
where G = gravitational constant
Therefore, the gravitational force acting between the student and the textbook is:
![\begin{gathered} F=(6.67430*10^(-11)*70*1)/(1^2) \\ \\ F=4.67*10^(-9)\text{ }N \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/ga75sxq2kezsvbgu3k533ocfct1j9p8chc.png)
That is the answer.