Question

Please help me with this problem I have been working on it but I keep getting it wrong this is my finale try please help.Solve for b. a = 9b²cA. b=±a√3cB. b=±ac√9C. b=±ac√3c D. b=±3ac−−√

Answer 1

To answer this question, we have to follow the next steps:

1. We have:

`a=9b^2c`

2. Divide both sides by 9c:

`\begin{gathered} (a)/(9c)=(9b^2c)/(9c)=(9c)/(9c)b^2 \\ (a)/(9c)=b^2 \end{gathered}`

3. Take the square root to both sides as follows:

`\begin{gathered} (a)/(9c)=b^2 \\ b^2=(a)/(9c) \\ \sqrt[]{b^2}=\pm\sqrt[]{(a)/(9c)} \\ \\ \\ \\ \end{gathered}`