Question

Solve and graph the inequality.8(3g−2)≤12(2g+1)please help lol

Answer 1

Given the inequality:

`8\cdot(3g-2)\leq12\cdot(2g+1)`

first we use the distributive property to get rid of the parenthesis:

`\begin{gathered} 8\cdot(3g-2)\le12\cdot(2g+1) \\ \Rightarrow24g-16\le24g+12 \end{gathered}`

Now we move the terms that got the variable g to the left side of the inequality, and the rest of the members go to the right side:

`\begin{gathered} 24g-16\le24g+12 \\ \Rightarrow24g-24g\le12+16 \\ \Rightarrow0\le28 \end{gathered}`

since we have that 0<=28 (and it's true), then the inequality is true for any value of g.