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Write the equation of the line:point = (9,-4); slope = -2/3

User Nocturnal
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ANSWER and EXPLANATION

We want to write the equation of the line that passes through (9, -4) and has a slope of -2/3.

To do that, we will use the point-slope method of writing a linear equation:


y-y_1=m(x-x_1)

where (x1, y1) = (9, -4)

m = slope = -2/3

Therefore, we have:


\begin{gathered} y\text{ - (-4) = }(-2)/(3)(x\text{ - 9)} \\ y\text{ + 4 = }(-2)/(3)x\text{ + 6} \\ \Rightarrow\text{ y = }(-2)/(3)x\text{ + 6 - 4} \\ y\text{ = }(-2)/(3)x\text{ + 2} \end{gathered}

User Karan Owalekar
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