Question

What is the derivative of e^2+ln(9)

Answer 1

We have the next function

`f(x)=e^2+\ln (9)`

And we must calculate f'(x).

Since we have a sum

`f^(\prime)(x)=(d)/(dx)e^2+(d)/(dx)\ln (9)`

Knowing that the derivative of a constant function is zero and e^2, ln(9) are constants we obtain

`\begin{gathered} f^(\prime)(x)=0+0=0 \\ \end{gathered}`

ANSWER:

`f^(\prime)(x)=0`