Question

-1 Find perimeter and area ofa rectanglewith dimensions (2x-2) and (3x+4)

Answer 1

The perimeter of the rectangle is ,

`P=2(l+w)`

The dimensions of the rectangles are,

`\begin{gathered} l=(2x-2) \\ b=(3x+4) \end{gathered}`

perimeter of the given rectangel is,

`\begin{gathered} P=2\lbrack(2x-2)+(3x+4)\rbrack \\ =2\lbrack2x-2+3x+4\rbrack \\ =2\lbrack5x+2\rbrack \\ =10x+4 \\ =2(5x+2) \end{gathered}`

The area of the rectangle formula is,

`\begin{gathered} A=l* w \\ =(2x-2)(3x+4) \\ =(6x+8x-6x-8) \\ =8x-8 \\ =8(x-1) \\ \end{gathered}`