Let's graph the 3 points given and name them accordingly.
The 3 points given are:
A = (-4, 3)
B = (4, 3)
C = (2, -3)
and the fourth point (the other vertex), we will label as D(x,y).
Since it is a parallelogram, we can say:
Midpoint AC = Midpoint BD
The midpoint formula between two points (x1, y1) and (x2, y2) is,
![M=((x_1+x_2)/(2),(y_1+y_2)/(2))](https://img.qammunity.org/2023/formulas/mathematics/high-school/azlty9lox0olsrspemwjd5v1udpdz43v6k.png)
This is basically the average of the x points and the average of the y points.
Now,
• Let's find ,midpoint AC,,
![\begin{gathered} A=(-4,3) \\ C=(2,-3) \\ ---------- \\ \text{Midpoint of AC,} \\ ((-4+2)/(2),(3-3)/(2))=(-1,0) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/223vgzd7yq8gx6eazjg856ugf81yqfqhnx.png)
• Let's find the expression for ,midpoint of BD,,
![\begin{gathered} B=(4,3) \\ D=(x,y) \\ --------- \\ \text{Midpoint of BD,} \\ ((4+x)/(2),(3+y)/(2)) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/2agaxmws030hx0m9arn4s62pv9ndkd1a15.png)
Since MIDPOINT AC = MIDPOINT BD, we can find x and y easily:
![\begin{gathered} (4+x)/(2)=-1 \\ 4+x=-2 \\ x=-2-4 \\ x=-6 \\ ----------- \\ (3+y)/(2)=0 \\ 3+y=0 \\ y=-3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gq1m8gin9mg5ps30bs08mv9hk6bfi64rf8.png)
Thus, the fourth coordinate is (x, y) = (-6, -3)
Answer(-6, -3)