Solution
- The equation of the path is:
![h(t)=h_0+23t-4.9t^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/4nywar40kth553y9vn7jymnizj80e99k2x.png)
- When the projectile hits the ground, the height of the projectile, i.e. h(t) = 0.
- We are told that the time when the projectile is on the ground is 5 seconds.
- Thus, when t = 5, h(t) = 0.
- We can use this information to solve the question as follows:
![\begin{gathered} h(t)=h_0+23t-4.9t^2 \\ put\text{ }h(t)=0,t=5 \\ \\ 0=h_0+23(5)-4.9(5)^2 \\ 0=h_0+115-122.5 \\ 0=h_0-7.5 \\ \text{ Add 7.5 to both sides} \\ \\ \therefore h_0=7.5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/48gcbw40enw6zt6zsuhfz7lnbn1zdjr1d0.png)
Final Answer
The answer is 7.5 meters