15.6k views
3 votes
a bag contains seven green Marbles and four white marbles. You select a marble at random. What are the odds in favor of picking a green marble.1) 7:112) 7:43) 4;74)3:7these are the options for answer

User Sumbul
by
7.8k points

1 Answer

3 votes

There are seven green marbles and four white ones; therefore, there are 7+4=11 marbles in the bag. Then, the odds of drawing a green marble are


\begin{gathered} odds=(probability)/(1-probability) \\ \Rightarrow odds(green)=((7)/(11))/(1-(7)/(11))=((7)/(11))/((4)/(11))=(7)/(4) \end{gathered}

Written as a ratio,


\Rightarrow odds(green)=7:4

Thus, the answer is 7:4, option 2.

User Bachlet Tansime
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories