Given: The scores on Felix first four test as below
![97,94,93,86](https://img.qammunity.org/2023/formulas/mathematics/college/sn8we4fafesjg7c2xrotc213843qkmrjkg.png)
To Determine: The fifth score if the average score is 92.2
Solution
Giving the formula below
![\bar{x}=(x_1+x_2+...+x_n)/(n)](https://img.qammunity.org/2023/formulas/mathematics/college/aixi3ykg5o0geo13zq76ue316pym3abe3n.png)
From the given
![\begin{gathered} \bar{x}=92.2 \\ x_1=97;x_2=94 \\ x_3=93;x_4=86 \\ x_5=? \\ n=5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/dpw54kuorrl5hfi4yzhivxt6gqa57yhqid.png)
Let us use the formula to get the fifth score as shown below
![\begin{gathered} (97+94+93+86+x_5)/(5)=92.2 \\ (370+x_5)/(5)=92.2 \\ 370+x_5=92.2*5 \\ 370+x_5=461 \\ x_5=461-370 \\ x_5=91 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ylcj6pfc9kuar0pkcf69oxj5v0iy5i6am6.png)
Hence, the score on the fifth test is 91