Step-by-step explanation:
Step 1:
We will calculate the total number of tosses made within the hour
![\begin{gathered} N=26+49+20+29 \\ N=124 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ecl03sdl5sx8d4rv3d1u2xrzexprsxixo2.png)
The number of times brown was tossed is given below as
![q=26](https://img.qammunity.org/2023/formulas/mathematics/college/wahfal38agk0y0h43u6ptr8obl5kuasnla.png)
Concept:
At least one of the sides is brown
As you do not know if the die is fair or not, the only way to approximate a probability of rolling a yellow is by making a table of frequencies and record the times you have rolled yellow.
If the number of tosses made in an hour is big enough as to draw a conclusion, then according to the Law of Large Numbers, the probability of rolling a brown in one toss of the die should be
![(q)/(N)](https://img.qammunity.org/2023/formulas/mathematics/college/w91ofpq78x6683z78p1w9uj94zmzntefzq.png)
By substituting the values, we will have
![\begin{gathered} (26)/(124)= \\ =0.2097 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3u7sefsxihsiorzze510fd4cac2tv1zzm2.png)
Hence,
The final answer is
![0.2097](https://img.qammunity.org/2023/formulas/mathematics/college/t5r2179msdyqw5n1e2dboq07oshg1ja30p.png)