Question

A bag of 13 marbles contains 5 marbles with red on them. 6 with blue on them, 6 with green on them, and 5 with red and green on them. What is the probability that arandomly chosen marble has either green or red on it? Note that these events are not mutually exclusive. Express your answer as a fraction in lowest terms or a decimalrounded to the nearest millionth.

Answer 1

P = 6/13

Step-by-step explanation:

There are 13 marbles in total. 5 of them are red and green, there are 5 marbles with red on them and there are 6 marbles with green on them.

Those 5 marbles with red on them are the same 5 marbles with red and green.

And from the 6 marbles with green on them, 5 of them are the same 5 with red and green.

So, the total number of marbles with red or green is 6 because there are:

5 marbles with red and green and 1 marble with red on it.

Therefore, the probability to chose a marble that has either green or red on it is:

`P=(6)/(13)`

So, the answer is 6/13