Step 1
The equation of a line in slope-intercept form is given as;
![\begin{gathered} y=mx+c \\ m=slope \\ c=y-intercept \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/tjliozr57pku15fqir4pz3v7thazpu8rix.png)
Considering the scatter plot of the graph it has a negative relationship as seen in the image.
This means that the slope of the graph is negative.
We, therefore, rule out all options with positive slopes such as;
![y=x-2\text{ and y=x+2}](https://img.qammunity.org/2023/formulas/mathematics/college/zo4c8cvjex8k6mpwk61p1s5k9t65ud8pz3.png)
Step 2
The scatterplot does not fall around the origin or below it, they rather shift up above zero.
Therefore the equation which could be a possible line of best fit for the scatterplot is;
![y=-x+2](https://img.qammunity.org/2023/formulas/mathematics/college/551n5vbye2kxs9qx8ygcrw5tw52xitf47z.png)
Answer;
![\begin{gathered} y=-x+2 \\ The\text{ scatterplot should have a positive intercept and is above the origin hence the answer} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fk3x6it9xhessb7sznx6eaohz1it8h4kv0.png)