Question

Factor out the following by taking out the GCF18cd^2+12c^2d+9cd

Answer 1

The given polynomial is:

`18cd^2+12c^2d+9cd`

The first step to factor taking out the GCF is to write each term in prime factored form, so:

`\begin{gathered} 18cd^2=2*3*3* c* d* d \\ 12c^2d=2*2*3* c* c* d \\ 9cd=3*3* c* d \end{gathered}`

The second step is to identify the factors common in all terms, they are: 3xcxd

Finally, factor out the GCF:

`3cd(6d+4c+3)`

The answer is above